InterviewSolution
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InterviewSolution
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For the reversible reaction, net rate is `2NO(g)+O_(2)(g) hArr 2NO_(2)(g)` `((dx)/(dt))_("net")=2.6 xx 10^(3)[NO]^(2)[O_(2)]-4.1 [NO_(2)]^(2)` If a reaction mixture contains 0.01 mol each of NO and `O_(2)` and 0.1 mol of `NO_(2)` in 1L closed flask, then above reaction isA. shifted in forward reactionB. shifted in backward reactionC. in equilibriumD. given values are incomplete |
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Answer» Correct Answer - B `K_(c )=(k_(f))/(k_(b))=(2.6 xx 10^(3))/(4.1)=6.34 xx 10^(2)` `Q_(c)=([NO_(2)]^(2))/([NO]^(2)xx[O_(2)])` `=([0.1 xx 1]^(2))/([0.01]^(2)[0.01])=10^(4)` i.e., `Q_(c )gt K` Hence the reaction shifts in backward direction so that reaction quotient `(Q_(c ))` approaches `K_(c )` |
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