1.

For the system 3A+2BhArrC, the expression for equilibrium constant K is

Answer»

`([3A]XX[2B])/([C])`
`([A]^(3)xx[B])/([C])`
`([C])/([A]^(3)xx[B]^(2))`
`([C])/([3A]xx[2B])`

Answer :C


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