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For the third electron of Lithium atom moving in its premissible orbit, the values of angular momentum and energy are...... Respectively |
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Answer» Angular momentum `(h)/(2PI)` energy `=(-9pi^(2)E^(4)m)/(2h^(2)` third ELECTRON of Li means `2s^(1)` `therefore` angular momentum quantum no = l =0 angularmomentum of electron in any orbital accordingto bohrequation`E=(2e^(4)pi^(2)z^(2)m)/(n^(2)h^(2))` for third electronof li `1s^(2) 2s^(1)` `=-9/2 (e^(4)pi^(2)m)/(h^(2))` |
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