1.

For the third electron of Lithium atom moving in its premissible orbit, the values of angular momentum and energy are...... Respectively

Answer»

Angular momentum `(h)/(2PI)` energy `=(-9pi^(2)E^(4)m)/(2h^(2)`
Angular momentum `(3h)/(2pi)` energy `=(+3pi^(2)em^(4))/(4h^(2)`
Angular momentum `(h)/(2pi)` energy `=(3pi^(2)me^(4))/(2h^(2)`
Angular momentum `(h)/(2pi)` energy `=(-6pi^(2)e^(4)m)/(3h^(2)`

Solution :`Li 1S^(2)2S^(1)`
third ELECTRON of Li means `2s^(1)`
`therefore` angular momentum quantum no = l =0 angularmomentum of electron in any orbital
accordingto bohrequation`E=(2e^(4)pi^(2)z^(2)m)/(n^(2)h^(2))`
for third electronof li `1s^(2) 2s^(1)`
`=-9/2 (e^(4)pi^(2)m)/(h^(2))`


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