For the two particles P and Q along the diametrically opposite end of a circle (r=4 m) as shown in figure at time t=0, origin is taken at centre of the circle. If Particle P moves 6 m towards Q, along line joining them. Then position of P with respect to Q will be:

For the two particles P and Q along the diametrically opposite end of

1.	For the two particles P and Q along the diametrically opposite end of a circle (r=4 m) as shown in figure at time t=0, origin is taken at centre of the circle. If Particle P moves 6 m towards Q, along line joining them. Then position of P with respect to Q will be:
Answer» For the two particles $P$ and $Q$ along the diametrically opposite end of a circle $(r = 4 m)$ as shown in figure at time $t = 0$ , origin is taken at centre of the circle. If Particle $P$ moves $6 m$ towards $Q$ , along line joining them. Then position of $P$ with respect to $Q$ will be:

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For the two particles P and Q along the diametrically opposite end of a circle (r=4 m) as shown in figure at time t=0, origin is taken at centre of the circle. If Particle P moves 6 m towards Q, along line joining them. Then position of P with respect to Q will be:

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