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For three events A,B and C P (exactly one of the events A or B occurs) = P(exactly one of the events B or C occurs) = P(exactly one of the events C ir A occurs) = P and P(all the three events occur simultaneously) `=P^(2)`, where `0ltplt(1)/(2)` Then the probability of at least one of the three events A,B and C occuring is :A. `(3p+2p^(2))/(2)`B. `(p+3p^(2))/(4)`C. `(p+3p^(2))/(2)`D. `(3p+3p^(2))/(4)` |
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Answer» Correct Answer - A P(exactly one of A or B occurs) `= P(A)+P(B)-2P(A nn B)` Similarly for B or C , C or A Adding all three, we get, `P(A)+P(B)+P(C )-P(A nn B)-P(B nn C)-P(C nn A)=(3p)/(2)` `P(A uu B uu C)=(3p)/(2)+p^(2)` |
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