For two gases A and B with molecular weights M_A and M_B, it is observed that at a certain temperature T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B if

For two gases A and B with molecular weights M_A and M_B, it is observ

1.	For two gases A and B with molecular weights M_A and M_B, it is observed that at a certain temperature T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B if
Answer» A is increased to a temperature `T_2 = (3 PI)/8 T` A is lowered to a temperature `T_2 = (8T)/(3pi)` B is increased to a temperature `T_2 = (3pi T)/8` B is lowered to a temperature `T_2 = (8T)/(3pi)` Solution :`(barC)_A = ( C)_B` `implies sqrt((8RT)/(pi M_A)) = sqrt((3RT)/(M_B)) implies 8/(pi M_A) = 3/(M_B) ` Case (i) changing T of A `(barC_A) = (barC)_B implies sqrt((8RT)/(pi M_A)) = sqrt((8RT_2)/(pi M_B))` `implies (T)/(M_A) = (T_2)/(M_B) implies T_2 = (M_B)/(M_A) T implies T_2 = (3pi)/(8) T > T.`