InterviewSolution
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InterviewSolution
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For water at 100∘C and 1 bar,ΔHvap−ΔUvapis x×102J mol−1The value of x (Round off to the Nearest Integer) is [Use : R=8.31 mol−1K−1][Assume volume of H2O(l) is much smaller than volume of H2O(g). Assume H2O(g) can be treated as an ideal gas] |
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Answer» For water at 100∘C and 1 bar, ΔHvap−ΔUvapis x×102J mol−1 The value of x (Round off to the Nearest Integer) is [Use : R=8.31 mol−1K−1] [Assume volume of H2O(l) is much smaller than volume of H2O(g). Assume H2O(g) can be treated as an ideal gas] |
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