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For what value of 'a' the block falls freely ? |
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Answer» Solution :In the time the wedge moves a distance x TOWARDS left with acceleration a the block FALLS through a HEIGHT h with acceleration g `(x=(1)/(2)at^(2))/(h=(1)/(2)g t^(2))rArr (x)/(h)=(a)/(g)` `rArr cot theta = (a)/(g) ""a=g cot theta` |
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