1.

For what value of a, the vector s `(2hati - 3hatj + 4hatk)` and `(ahati + 6hatj - 8hatk)` collinear ?

Answer» The given vectors are collinear only when
`(ahati + 6hatj - 8hatk) = lambda(2hati - 3hatj + 4hatk)`
for some nonzero scalar `lambda` .
Now, `ahati + 6hatj - 8hatk = 2lambda hati - 3lambda hatj + 4lambdahatk`
`hArr 2lambda = a , - 3lambda = 6` and `4lambda = - 8`.
`hArr = a/2` and `lambda = - 2 hArr a/2= - 2 hArr a = - 4`
Hence the given vectors are collinear when `a = - 4`.


Discussion

No Comment Found