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For what value of k does the matrix. A = \(\begin{bmatrix}k & -1 \\3 & 2\end{bmatrix}\)does not have inverse?(a) 1(b) -3/2(c) 0(d) -1 |
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Answer» (b) -3/2 For A = \(\begin{bmatrix} k & -1 \\ 3 & 2 \end{bmatrix}\) , if |A| = 0, then inverse does not exists \(\begin{vmatrix} k & -1 \\ 3 & 2 \end{vmatrix}\) = 0 gives 2k + 3 = 0 gives 2k + 3 = 0 or k = -3/2 |
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