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For what value of k does the system of equations `x+2y=3` and `5x + ky + 7 = 0` have no solutionA. ` k = 10 `B. ` k ne 10 `C. ` k = (-7)/(3)`D. ` k = - 21 ` |
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Answer» Correct Answer - A For no solution, we have ` (a_1)/(a_2) = (b_1)/(b_2) ne (c_1)/(c_2)`. ` therefore (1)/(5) = (2)/(k) ne (-3)/(7) rArr k = 10 and k ne (-14)/(3)`. Hence, ` k = 10 `. |
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