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For what value of k, will the expression (3x3 – kx2 + 4x + 16) be divisible by (x –\(\frac{k}{2}\)) ?(a) 4 (b) –4 (c) 2 (d) 0 |
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Answer» (b) – 4. Let f(x) = 3x3 – kx2 + 4x + 16. Then, f(x) will be divisible by \(\big(\)x – \(\frac{k}{2}\)\(\big)\) if f\(\big(\frac{k}{2}\big)\) = 0 ⇒ 3.\(\big(\frac{k}{2}\big)\)3 – k.\(\big(\frac{k}{2}\big)\)2 + 4\(\big(\frac{k}{2}\big)\) + 16 = 0 ⇒ \(\frac{3k^3}{8}\) - \(\frac{k^3}{4}\) + \(\frac{4k}{2}\) + 16 = 0 ⇒ \(\frac{3k^3-2k^3+16k+128}{8}\) = 0 ⇒ k3 + 16k + 128 = 0 ⇒ (k + 4) (k2 – 4k + 32) = 0 ⇒ k + 4 = 0 ⇒ k = – 4. |
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