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For what value of lambda is the function defined by f(x)={{:(lambda(x^(2)-2x)," if "x le 0),(4x+1," if "x gt 0):} continuous at x= 0? What about continuity at x =1?

Answer»


Answer :For no VALUE of `lambda`, f is continuous at X= 0 but f is continuous at x=1 fo any value of `lambda`.


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