for what value of p the quadratic equation have equal roots (p6+1)x²+

1.	for what value of p the quadratic equation have equal roots (p6+1)x²+2(p+3)x+(p+8)=0 by using b²-4ac=0
Answer» <P>Ans:- as the roots are equal D = b^2 -4AC = 0 (p+3)^2 - 4(6p+1)(p+8) = 0 p^2 +6p +9 - 4(6p^2+ 49p +8) = 0 p^2 + 6p +9 - 24p^2 - 196p - 32 = 0 23p^2 + 190p - 23 = 0 by applying quadratic formula p = (- 95 + √9554)/23 and (- 95 + √9554)/23 Step-by-step explanation:Hope you liked the solution . Please mark me as BRAINLIEST

for what value of p the quadratic equation have equal roots (p6+1)x²+2(p+3)x+(p+8)=0 by using b²-4ac=0

Answer»

<P>Ans:- as the roots are equal

D = b^2 -4AC = 0

(p+3)^2 - 4(6p+1)(p+8) = 0

p^2 +6p +9 - 4(6p^2+ 49p +8) = 0

p^2 + 6p +9 - 24p^2 - 196p - 32 = 0

23p^2 + 190p - 23 = 0

by applying quadratic formula

p = (- 95 + √9554)/23 and (- 95 + √9554)/23

Step-by-step explanation:Hope you liked the solution . Please mark me as BRAINLIEST