1.

For what value of x, in the median of the following frequency distribution 34.5 ?ClassFrequency0-10310-20520-301130-401040-50x50-60360-702

Answer»
ClassFrequencyC.F.
0-1033
10-2058
20-301119
30-401029
40-50xx + 29
50-603x + 32
60-702x + 34

Median = 30 + \(\cfrac{(\frac{34+x}2-19)}{10}\times 10\)

34.5  = 30 + \(\frac{34 + x - 38}2\)

⇒ 34 + x - 38 = (34.5 - 30)2 = 9

⇒ x = 9 + 4 = 13



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