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For what value of x, in the median of the following frequency distribution 34.5 ?ClassFrequency0-10310-20520-301130-401040-50x50-60360-702 |
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Answer»
Median = 30 + \(\cfrac{(\frac{34+x}2-19)}{10}\times 10\) 34.5 = 30 + \(\frac{34 + x - 38}2\) ⇒ 34 + x - 38 = (34.5 - 30)2 = 9 ⇒ x = 9 + 4 = 13 |
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