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For what values of k, the equation `kx^(2)-6x-2=0` has real roots?A. `kle(-9)/(2)`B. kge(-9)/(2)`C. `kle-2`D. None of these

Answer» Correct Answer - B
For real roots, we must have `b^(2)-4acge0.`
`:." "(-6)^(2)-4xxkxx(-2)ge0implies36+8kge0`
`implies8kge-36implieskge(-9)/(2).`


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