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For which change `DeltaH ne DeltaE` :A. `H_(2)+I_(2)rarr2HI`B. `HCl+NaOHrarrNaCl`C. `C_((s))+O_(2(g))rarrCO_(2(g))`D. `N_(2)+3H_(2)rarr2NH_(3)` |
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Answer» Correct Answer - D `DeltaH=DeltaE+DeltanRT` `therefore` For `DeltaH ne DeltaE. Deltan ne 0` `Deltan=0` for reaction (a) as both reactants & products have same no. of molecules `Deltan=0` for (c ) as C is in solid state. Further `DeltaH=DeltaE` for reaction (b) as it is carried out in liquid state Moreover `Deltan=0` for this reaction also, `HCl+NaOHrarrNaCl+H_(2)O`. |
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