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For which value of x, matrix \(\begin{bmatrix}1&-2&3\\[0.3em]1&2&1\\[0.3em]x&2&-3\end{bmatrix}\) is singular ? |
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Answer» Then \(\begin{bmatrix}1&-2&3\\[0.3em]1&2&1\\[0.3em]x&2&-3\end{bmatrix}\) = 0 ⇒ 1 (- 6 – 2) + 2 (-3 – x) + 3(2 – 2x) = 0 ⇒ -8 – 6 – 2x + 6 – 6x = 0 ⇒ -8 = 8 ⇒ x = 8/-8 = -1 Hence, x = -1 |
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