InterviewSolution
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For x > 0, Let A=⎡⎢⎣x+1x000x00016⎤⎥⎦B=⎡⎢⎢⎢⎣5xx2+10003x00014⎤⎥⎥⎥⎦ X=(AB)−1+(AB)−2+(AB)−3+...∞ Z=X−1−2I (I is identity matrix of order 3) (P) minimum value of [Tr(Ax)]is(1)24(when [.])→represent integer function(Q) det(X−1) is(2)12(R) If Tr(z+z2+−−−+z10)=2a+b,(a,b∈N)then a + b is (3)6(S) If value of |adj(√5X−1)|=kthen number of positive divisors(4)19of k which are odd is |
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Answer» For x > 0, Let A=⎡⎢⎣x+1x000x00016⎤⎥⎦B=⎡⎢ |
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