1.

For x inR, f(x) is defined as follows : f(x)={{:(x+1,,0lexlt2),(|x-4|,,x ge 2):} Then the solution set of the equation isf(x)^(2)+x=f(x)+x^(2) is

Answer»

`{-1,1}`
`[2,OO)`
`[0,2)`
{0,2}`

ANSWER :(d)


Discussion

No Comment Found

Related InterviewSolutions