For x∈R, x≠0 if y(x) is a differentiable function such that xx∫1 – InterviewSolution

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1.	For x∈R, x≠0 if y(x) is a differentiable function such that xx∫1y(t) dt=(x+1)x∫1t y(t) dt, then y(x) equals:
Answer» For $x \in R, x \neq 0$ if $y (x)$ is a differentiable function such that $x x \int 1 y (t) d t = (x + 1) x \int 1 t y (t) d t,$ then $y (x)$ equals:

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