Force (5, 6, 7) N acts on a particle with position vector (2, 2, 1) m. The magnitude of phi torque on the particle will be ………. Nm.

Force (5, 6, 7) N acts on a particle with position vector (2, 2, 1) m.

1.	Force (5, 6, 7) N acts on a particle with position vector (2, 2, 1) m. The magnitude of phi torque on the particle will be ………. Nm.
Answer» <html><body><p>`sqrt(13)`<br/>`sqrt(149)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/61-330126" style="font-weight:bold;" target="_blank" title="Click to know more about 61">61</a>)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)`</p>Solution :`\|vectau\|=\|vecrxxvecF\|` <br/> `=\|(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>,2,1)xx(5,6,7)\|` <br/> `=\|(2,2,1)xx(5,6,7)\|` <br/> `=\|hati(14-6)-<a href="https://interviewquestions.tuteehub.com/tag/hatj-2693584" style="font-weight:bold;" target="_blank" title="Click to know more about HATJ">HATJ</a>(14-5)+hatk(12-10)\|` <br/> `=\|8hati-9hatj+2hatk\|` <br/> `=sqrt((8)^(2)+(-9)^(2)+(2)^(2))` <br/> `=sqrt(64+81+4)` <br/> `=sqrt(149)`</body></html>