1.

Force acting on a particale is `(2hat(i)+3hat(j))N`. Work done by this force is zero, when the particle is moved on the line `3y+kx=5`. Here value of k is `(`Work done `W=vec(F).vec(d))`A. 2B. 4C. 6D. 8

Answer» Correct Answer - A
Given, `F=2hat(i)+3hat(j)`
displacement `ds=dx hat(i)+dyhat(j)+dz hat(k)`
work done, `w=int F.ds =int (2 dx+3dy)`
Also `3y+kx=5 implies (3dy)/(dx)+k=0`
`implies 3dy=-kdx implies W=int (2dx-kdx)=0`
`implies 2x=kx implies k=2`


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