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Force between two charges placed at a distance r in vacuum is F .Now a dielectric slab of K =4 is inserted between them .its thickness is r/2.The new force between the charges F/4 F/2. 3F/5. 4F/9.

Answer» Force between two charges placed at a distance r in vacuum is F .Now a dielectric slab of K =4 is inserted between them .its thickness is r/2.The new force between the charges F/4 F/2. 3F/5. 4F/9.


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