Force F on the particle of mass 0.1 kg varies with distance x as shownin figure . If particle with distancex as shown in figure .If particlemove from rest x = 0 , that at x = 12 cm , what will be its velocity ?

Force F on the particle of mass 0.1 kg varies with distance x as shown

1.	Force F on the particle of mass 0.1 kg varies with distance x as shownin figure . If particle with distancex as shown in figure .If particlemove from rest x = 0 , that at x = 12 cm , what will be its velocity ?
Answer» Solution :Work W = Area of isoscles trapezoid OABC ` =1/2 {:{("sumof sides"),(of " parallelogram"):}}xx{("perpendicular DISTANCE"),("between sides of parallelogram"):}}` ` =1/2 (AB +OC) xx(BD)` ` =1/2 (4+12)xx(10)` ` = 80 J ` `rArr` Now according to work energy theorem , `W =K_(f) -K_(0)` ` :.80 =1/2 mv_(f)^(2) -1/2mv_(i)^(2)` ` :.80 =1/2 mv_(f)^(2) "" [ :. v_(i) = 0] ` ` 80 =1/2 xx0.1 xxv^(2)` ` :. 1600 =v^(2)` ` :. v = 40 m^(-1)`