Force of 4 N is applied on a body of mass 20 kg. The work done in 3^(r

1.	Force of 4 N is applied on a body of mass 20 kg. The work done in 3^(rd) second is
Answer» 3 joule 2 joule 4 joule 1 joule Solution :`a = F/M = 4/20 = 1/5 m//s^2` `S = 1/2 at^2 = 1/2 xx 1/5 xx 3 xx 3` work done in 3 SECOND = ` 4 xx 1/2 xx 1/5 xx 3 xx 3 = 18/5 ` Joule Work done in 2 second = `4 xx 1/2 xx 1/5 xx 2 xx 2 = 8/5 `Joule Work done in `3^(RD)` second = `18/5 - 8/5= 10/5 = 2` Joule.

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