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Force on a current carrying conductor in a magnetic field is -(A) \(\vec{F} = \frac{(\vec{l} \times \vec{B})}{I}\)(B) \(\vec{F} = l(\vec{l} \times \vec{B})\)(C) \(\vec{F} = \frac{(\vec{B} \times \vec{l})}{I}\)(D) \(\vec{F} = l(\vec{B} \times \vec{l})\) |
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Answer» Correct answer is (B) \(\vec{F} = l(\vec{l} \times \vec{B})\) |
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