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formation of lolyethylene from cac2 takes place as cac2 + 2h2o→ ca(oh)2 + c2h2 c2h2+ h2 → c2h4 nC2H2→(-ch2-ch2)n the amount of polyethylene obtained from 64 kg of cac2 is 1.7 kg 2.14kg 3.21 kg 4.28 k |
| Answer» formation of lolyethylene from cac2 takes place as cac2 + 2h2o→ ca(oh)2 + c2h2 c2h2+ h2 → c2h4 nC2H2→(-ch2-ch2)n the amount of polyethylene obtained from 64 kg of cac2 is 1.7 kg 2.14kg 3.21 kg 4.28 k | |