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Formation of polyethylene from calcium carbide takes place as follows `CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)` `C_(2)H_(2)+H_(2) rarr C_(2)H_(2)` `N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)` The amount of polyethylene obtained from `64.1 kg CaC_(2) ` isA. 7kgB. 14kgC. 21kgD. 28kg |
Answer» Correct Answer - D 64kg of `CaC_(2)` produces ethylene=28kg Amount of polythene produced=28kg |
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