Formula of cane sugar is C_(12)H_(22)O_(11). No. of molecules present in 34.2 g of cane sugar is

Formula of cane sugar is C_(12)H_(22)O_(11). No. of molecules present

1.	Formula of cane sugar is C_(12)H_(22)O_(11). No. of molecules present in 34.2 g of cane sugar is
Answer» `6.022 xx 10^(21)` `6.022 xx 10^(20)` `6.022 xx 10^(22)` `6.022 xx 10^(18)` Solution :Gram molecular mass of cane SUGAR `(C_(12)H_(22)O_(11))` `= 12xx12 +22 xx 1 +16 xx11` `= 342.0 G` 342.0 g of can sugar contain `=6.022 xx 10^(23)` MOLECULES 34.2 g of cane sugar contain `= (34.2)/(342)xx6.022xx10^(23)` `=6.022 x 10^(22)` molecules.