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Forr 14 g of CO, the wrong statement isA. it occupies `2.24` L at NTPB. It correspends to `1//2` mole of COC. It corresponds ot same mole of CO and nitrogen gasD. it corresponds to `3.01xx 10 ^(23)` molecules of CO |
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Answer» Correct Answer - A 28 g of CO occuupies `= 22.4` L of CO at NTP `therefore` 14 g of CO occupies `=22.4/28 xx 14 ` L of CO at NTP `= 11, 2 ` L of CO at NTP Thus, 14 g of CO occupies `11.2` L volume at NTP. Thus, given statement is wrong. |
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