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Four capacitor and a battery of `emf 24 V` are connected as shown in the figure. Initially, `S` is open and the capacitors are uncharged. After `S` is closed and steady state is attained, the potential difference across the `4 mu f` capacitor is `7.5 V`. The capacitance in `mu f` of the capacitor `A` is. .A. 5B. 7C. 8D. 10 |
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Answer» Correct Answer - D P.d across the plates of `A=24-[7.5+(7.5 xx4)/(3)]=6.5 V` Charge on `A=(17.5 xx2)+(4xx7.5)=65 muc` `:.` Capacitance of `A=(65)/(6.5)=10 muf`. |
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