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Four capacitors and two batteries are connected as shown in the diagram. The `p.d` between the points `a` and `b` is .A. 22 VB. 15 VC. 13 VD. 0 V |
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Answer» Correct Answer - C P.D across `2mu F` capacitor is `(22-7) xx (3)/((3+2))=9V` p.d across `8 muF` capacitor is `= 22V` As the positively charged plates of `2 muF` and `8 muF` are connected `V_(a)-V_(b) = 22-9 = 13 V`. |
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