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Four capacitors, C1, C2, C3 and C4 are connected as shown in figure below. Calculate equivalent capacitance of the circuit between points X and Y. |
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Answer» The given arrangement of capacitors can be analysed as below. The combination of capacitors C2 and C3 of capacity 30 μF and 20 μF are in series, their combined capacity is given by C' = \(\frac{30\times20}{50}\) = 12μF The capacitor C’ is in parallel with C4, their combined capacity C” is given by C'' = 12 + 28 = 40μF Now, C1 and C” are in series. ∴ Net capacity of the combination is given by C = \(\frac{40\times10}{50}\) = 8μF |
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