Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die isA. `1//6`B. `1//36`C. `12//151`D. none of these

Four die are thrown simultaneously. The probability that 4 and 3 appea

1.	Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die isA. `1//6`B. `1//36`C. `12//151`D. none of these
Answer» Correct Answer - C Given that 5 and 6 have appeared on two of the dice, the sample space reduces to `6^(4) - 2 xx 5^(4) + 4^(4)` (inclusion-exclusion principle). Also, the number of favorable cases are `4! = 24`. So, the required probability is `24//302 = 12//151`.

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Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die isA. `1//6`B. `1//36`C. `12//151`D. none of these

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