1.

Four engines are working between Which one has maximum efficiency ?

Answer»

100 K and 80 K
40 K and 20 K
60 K and 40 K
120 K and 100 K

Solution :EFFICIENCY, `ETA = 1 - (T_(2))/(T_(1)) = (T_(1) - T_(2))/(T_(1))`
In all the given four cases,
`T_(1) - T_(2) = 20 K`
`:. eta` is highest when `T_(1)` is LOWEST.
`:.` At option (b), 40 K and 20 K, has maximum efficiency.


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