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Four friends born between (1991 – 99) meets at 2020. The ratio of sum of age of two oldest guys: Sum of age two youngest guys is 9 ∶ 8. Again when they meet at 2030, the ratio of (sum age of youngest + oldest) and (sum of ages of other two) is 1 ∶ 1. What is the sum of the age of the third youngest guy and second youngest guy in the year 2020? (in years)1. 512. 523. 534. 545. 55 |
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Answer» Correct Answer - Option 1 : 51 If all the 4 people were born between 1991 – 99, their ages at 2020 should be in the range 21 – 29 By year 2020 Let the age of the guys (from youngest to oldest) in the year 2020 be p, q, r and s respectively Let sum of ages of two oldest guys and sum of ages two youngest guys be 9a and 8a respectively 9a and 8a should lie between 42 – 58 (Because sum of two people) Only such value is possible when a = 6 Sum of ages of two youngest = p + q = 48 ---- 1 Sum of ages of two oldest = r + s = 54 ---- 2 By the year 2030 Their ages will be p + 10, q + 10, r + 10 and s + 10 Sum of ages of oldest + youngest: Sum of ages of other two guys = 1 ∶ 1 ⇒ p + s + 20 = q + r + 20 ∴ p + s = q + r Equation 1 + Equation 2 ⇒ p + s + q + r = 102 ⇒ 2 × (q + r) = 102 ⇒ q + r = 51 years ∴ The sum of the age of the third youngest guy and second youngest guy in the year 2020 is 51 years. |
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