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Four grams of graphite is burnt in a bomb calorimeter of heat capacity `30 kJ K^(-1)` in excess of oxygen at 1 atmospheric pressure. The temperature rises from 300 to 304 K. What is the enthalpy of combustion of graphite (in kJ `mol^(-1)`)A. 360B. 1440C. `- 360`D. `- 1440` |
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Answer» Correct Answer - C `DeltaE=CxxDeltatxx(M)/(m)=30xx4xx(12)/(4)=360` `DeltaE=-360 kJ mol^(-1)` |
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