Four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12grams of CO_(2). What is the empirical formula of the hydrocarbon ? (C = 12, H = 1)

Four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12g

1.	Four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12grams of CO_(2). What is the empirical formula of the hydrocarbon ? (C = 12, H = 1)
Answer» `CH_(3)` `C_(4) H_(9)` `CH` `C_(3) H_(8)` Answer :D