four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12grams of CO_(2). What is the empirical formula of the hydrocarbon ? (C=12 , H=1)

four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12g

1.	four grams of hydrocarbon (C_(x)H_(y)) on complete combustion gave 12grams of CO_(2). What is the empirical formula of the hydrocarbon ? (C=12 , H=1)
Answer» `CH_(3)` `C_(4)H_(9)` CH `C_(3)H_(8)` ANSWER :D