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Four identical thin rods each of mass `M` and length `l`, from a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane isA. `(4)/(3) Ml^2`B. `(2)/(3) Ml^2`C. `(13)/(3) Ml^2`D. `(1)/(3) Ml^2` |
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Answer» Correct Answer - A (a) The moment of inertia of rod about an axis through its centre of mass and perpendicular to rod + (mass of rod) xx (perpendicular distance between two axes) =`(Ml^2)/(12) + M((l)/(2))^2 = (Ml^2)/(3)` Moment of inertia of the system `= (Ml^2)/(3) xx 4` =`(4)/(3) Ml^2`. |
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