InterviewSolution
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InterviewSolution
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Four moles of an ideal gas is initially in state `A` having pressure ` 2 xx 10^(5) N//m^(2)` and temperature ` 200 K` . Keeping the pressure constant the gas is taken to state `B` at temperature of `400K`. The gas is then taken to a state `C` in such a way that its temperature increases and volume decreases. Also from `B` to `C` , the magnitude of `dT//dV` increases. The volume of gas at state `C` is eqaul to its volume at statem `A`. Now gas is taken to initial state `A` keeping volume constant. A total `1000 J` of heat is withdrawn from the sample of the cyclic process . Take `R=8.3 J// K// mol`. The volume of gas at state `C` isA. `0.0332 m ^(3)`B. `0.22 m^(3)`C. `0.332m ^(3)`D. `3.32 m ^(3)` |
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Answer» Correct Answer - A The volume of gas at state `C` is `V_(C)=V_(A)=(nRT_(A))/(P_(A))` `=0.0332m^(3)` |
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