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Four particles are fired with the same velocities at angles 250^@, 40^@, 55^@ and 70^@with the horizontal. The range of projectile will be largest for the one projected at angle |
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Answer» Solution :`R=(u^2sin2 THETA)/(G)` In this case, `sin2theta` is the largest for ` theta = 40^@` , as compared to that for `theta = 25^@ , 55^@ , 70^@` . |
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