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Four particles of masses 1kg, 2kg, 3kg and 4kg are placed at the four vertices A,B,C and D of the square of side 1 m. Find the position of centre of mass of the particles. |
Answer» Solution :Assuming A as the origin , AB x-axis and AD as y-axis we have Co-ordinates of their CM are `x_(CM)=(m_(1)x_(1)+m_(2)x_(2)+m_(3)x_(3)+m_(4)x_(4))/(m_(1)+m_(2)+m_(3)+m_(4))` `=((1)(0)+2(1)+3(1)+4(0))/(1+2+3+4)=0.5m` Similarly, `y_(CM)=(m_(1)y_(1)+m_(2)y_(2)+m_(3)_(3)+m_(4)y_(4))/(m_(1)+m_(2)+m_(3)+m_(4))` `=(1(0)+2(0)+3(1)+4(1))/(1+2+3+4)=0.7m` `:.` Co-ordinate of CENTRE of mass `(X_(CM),y_(CM))=(0.5m,0.7m)` |
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