1.

Four point masses, each of value m, are placed at the corners of a square ABCD of side 1. The moment of inertia of this system about an axis through A and parallel to BD is

Answer»

`ml^2`
`2ml^2`
`sqrt3 ml^2`
`3ml^2`

Solution :`AO = cos 45^(@) = (l)/(2)`
`THEREFORE AO xx (1)/(sqrt2)= (l)/(2)`
or `AO = (l)/(sqrt2)`
`I = I_(D) + I_(B) + I_(C)`
or `I = (2ml^2)/(2) + m ((2L)/(sqrt2))^(2)`
= `(2ml^(2))/(2) + (4ml^2)/(2)`
or `I = (6ml^2)/(2) = 3ml^2`


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