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Four resistances are connected in a circuit in the given figure. The electric cirrent flowing through `4 ohm` and `6 ohm` resistance is respectively A. 2A and 4AB. 1A and 2AC. 1A and 1AD. 2A and 2A |
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Answer» Correct Answer - D Resistance of `4 Omega` and `4 Omega` are in parallel, their equivalent resistance `= 2 Omega` Similarly, equivalent resistance of `6 Omega` and `6Omega = 3 Omega` Now `2 Omega` and `3 Omega` are in series, hence their total resistance `R = 2+3=5 Omega` From `V = iR rArr i = (V)/(R )=(20)/(5)=4 A` This current will be equally divided in `4 Omega` and `6 Omega` resistance So, current through `4 Omega` and `6 Omega` resistance is 2A respectively. |
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