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Four resistances of `16 Omega , 12 Omega , 4 Omega and 9 Omega` respectively are connected in cycle order so from a Wheatstone bridge. Calculate the resistance in be connected in parallel with `9 Omega` resistance to balance the bridge.A. `13.5Omega`B. `15.5Omega`C. `27Omega`D. `12Omega` |
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Answer» Correct Answer - A To balance the bridge equivalent resistance of `R_(4)` and shunt x should be `9 Omega` `:.R_(P)=(R_(4)xx x)/(R_(4)+ x)` `9=(27 xx x)/(27 + x) :.x=13.5Omega`. |
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