1.

Four years ago, a father was three times as old as his daughter then was. In 8 vears times.he will be twice as old as his daughter will then be. Find their present ages

Answer»

let fathers age be X and daughters age be ynow as y=3x which was 4 years backso present ages will bex+4 and 3x+4 of father and daughter respectivelyin 8 years time2(X+4+8)=3x+4+8hence2x+24=3x+12x=12hence age of daughter is 12and father is 3x+4=3*12+4=40


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