1.

\(\frac{1}{\sqrt9-\sqrt8}\) is equal toA. 3 + 2√2B. \(\frac{1}{3+2\sqrt2}\)C. 3 - 2√2D. \(\frac{3}{2}\) - √2

Answer»

\(\frac{1}{\sqrt9-\sqrt8}\)

= \(\frac{1}{\sqrt9-\sqrt8}\) × \(\frac{\sqrt9 + \sqrt8}{\sqrt9+\sqrt8}\)

= √9 + √8 = 3 + 2√2



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