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\(\frac{1}{\sqrt9-\sqrt8}\) is equal toA. 3 + 2√2B. \(\frac{1}{3+2\sqrt2}\)C. 3 - 2√2D. \(\frac{3}{2}\) - √2 |
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Answer» \(\frac{1}{\sqrt9-\sqrt8}\) = \(\frac{1}{\sqrt9-\sqrt8}\) × \(\frac{\sqrt9 + \sqrt8}{\sqrt9+\sqrt8}\) = √9 + √8 = 3 + 2√2 |
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