1.

\(\frac{1}{x+1}-\frac{1}{x-1}-\frac{x^2}{x+1}+\frac{x^2}{x-1},\) when simplified is equal to :(a) 0 (b) 1 (c) 2 (d) –2

Answer»

(c) 2

\(\frac{1}{x+1}-\frac{1}{x-1}-\frac{x^2}{x+1}+\frac{x^2}{x-1}\)

= \(\frac{(x-1)-(x+1)-x^2(x-1)+x^2(x+1)}{(x-1)(x+1)}\)

= \(\frac{x-1-x-1-x^3+x^2+x^3+x^2}{x^2-1}\)

= \(\frac{2x^2-2}{x^2-1}=\frac{2(x^2-1)}{(x^2-1)}\) = 2


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